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13x^2-3x-304=0
a = 13; b = -3; c = -304;
Δ = b2-4ac
Δ = -32-4·13·(-304)
Δ = 15817
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{15817}}{2*13}=\frac{3-\sqrt{15817}}{26} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{15817}}{2*13}=\frac{3+\sqrt{15817}}{26} $
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